We have that
x² − 8xy + y²<span> = 8
</span>2x-8y-8x(dy/dx)+2y*(<span>dy/dx)=0
</span>8x(dy/dx)-2y*(dy/dx)=2x-8y
[8x-2y]*(dy/dx)=2x-8y
(dy/dx)=[2x-8y]/[8x-2y]
(dy/dx)=2*[x-4y]/2*[4x-y]
(dy/dx)=[x-4y]/[4x-y]
the answer is
(dy/dx)=[x-4y]/[4x-y]
Answer:
Negative 4 n + 8 + 9 n minus 2 and 5 n + 6
Step-by-step explanation:
3v + 5 - (9v + 2)
3v + 5 - 9v -2 = -6v + 3
-6v + 6
(NO)
-6n + 3 - (2n + 2)
-6n + 3 - 2n - 4 = -8n - 1
-8n + 6
(NO)
-4n + 8 + 9n - 2 = 5n + 6
5n + 6
(YES)
<span>a1= (which is the first term.)
to find the 2nd term you plug in 2 for (an) in the formula given to you. =-4(2-1)^2 *remember an represents the term u are looking for *
now you start to solve it
-4(2-1)^2
-4 (1)^2
.
-4^2
= 16
so your first two terms are 2 and 16 .</span>
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