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2 years ago

What is the perimeter of the parallelogram?

Mathematics

2 answers:

Ganezh [65]2 years ago

5 0

Answer:

Step-by-step explanation:

Luba_88 [7]2 years ago

3 0

The answer is 12 when you add the base and height of the parallelogram and multiply by2

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For the pair of similar triangles, find the value of x. <br><br> The value of x is .

inysia [295]

Answer:

18.

Explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

7 0

2 years ago

Subtract the sum of the expressions (4x2 – 6x + 3) and (-5x2 + 5x + 2) from the sum of (7x2 – 8x + 2) and (6x2 – 3x + 8)

snow_lady [41]

Answer: [6x]

Step-by-step explanation:

(8 - 9x) = [1x]

(-10 + 7x) = [17x]

(14 - 16x) = [2x]

(12 - 24x) = [12x]

12x - 2x - 17x - 1x =

10x - 16x = [6x]

3 0

2 years ago

ALGEBRA 1, SEM. 2

romanna [79]

This is [ (f(2) - f(-2) ] / ( 2 - (-2)

= 1/16 - 16 / 4

= -255/64

= -3 63/64

6 0

2 years ago

Really easy math problem 5pts!!!

kogti [31]

You're given two angles and the side not between them are congruent, so the AAS theorem applies. (2nd selection)

4 0

2 years ago

Read 2 more answers

About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex

enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .$

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.$

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by $\dfrac{2}{3}$ .

8 0

2 years ago