A pool supply company sells 50-pound buckets of chlorine tablets. A customer believes that the company may be underfilling the b
uckets. To investigate, an inspector is hired. The inspector randomly selects 30 of these buckets of chlorine tablets and weighs the contents of each bucket. The sample mean is 49.4 pounds with a standard deviation of 1.2 pounds. The inspector would like to know if this provides convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds, so he plans to test the hypotheses H0: μ = 50 versus Ha: μ < 50, where μ = the true mean weight of all 50-pound buckets of chlorine tablets. The conditions for inference are met. The test statistic is t = –2.74 and the P-value is between 0.005 and 0.01. What conclusion should be made at the significance level, Alpha? Reject H0. There is convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds.
Reject H0. There is not convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds.
Fail to reject H0. There is convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds.
Fail to reject H0. There is not convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds.
The answer is: Reject H0. There is convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds.
Step-by-step explanation: Well there are 5 cats and each cat drinks .15 liters per day. .15x5 = .75 liters of water. 1.55 liters - .75 liters = 0.8 liters left.
We need to evaluate if thickness of a 10 gauge metal sheet is a requiered in the process that means 3.416 mm thick. So that should be our null hypothesis; μ₀ = 3.416 and based on sample data, we will formulate an alternative hypothesis taking into account the mean, and standard deviation obtained. We surely will have better information to take a decision