To find the slope<span> and y </span>intercept<span>, use the </span><span>y=mx+b</span> formula<span> where </span>m<span> is the </span>slope<span> and </span>b<span> is the y </span>intercept<span>.
</span><span>y=mx+b
</span>Pull the values of m<span> and </span>b<span> using the </span><span>y=mx+b</span> formula<span>.
</span><span>m=<span>7/2</span>,</span><span>b=−2</span><span> where m is the </span>slope<span> and b is the </span>y-intercept
The answer to this problem would be B because your going up by 6
48 inches = 4 feet, therefore 4:2, but simplified it is B. 2:1
Answer:
HCF Of two nos. is 17
Let another no. be x
we know that HCF ×LCM = Product of two numbers
17×140=20×(x)
20x=2380
x =2380/20
x=119
The other no. is 119
Answer:
(a) The probability of getting someone who was not sent to prison is 0.55.
(b) If a study subject is randomly selected and it is then found that the subject entered a guilty plea, the probability that this person was not sent to prison is 0.63.
Step-by-step explanation:
We are given that in a study of pleas and prison sentences, it is found that 45% of the subjects studied were sent to prison. Among those sent to prison, 40% chose to plead guilty. Among those not sent to prison, 55% chose to plead guilty.
Let the probability that subjects studied were sent to prison = P(A) = 0.45
Let G = event that subject chose to plead guilty
So, the probability that the subjects chose to plead guilty given that they were sent to prison = P(G/A) = 0.40
and the probability that the subjects chose to plead guilty given that they were not sent to prison = P(G/A') = 0.55
(a) The probability of getting someone who was not sent to prison = 1 - Probability of getting someone who was sent to prison
P(A') = 1 - P(A)
= 1 - 0.45 = 0.55
(b) If a study subject is randomly selected and it is then found that the subject entered a guilty plea, the probability that this person was not sent to prison is given by = P(A'/G)
We will use Bayes' Theorem here to calculate the above probability;
P(A'/G) = 
= 
= 
= <u>0.63</u>
