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2 years ago

How do you find the circumference, radius, and diameter in area?

Mathematics

1 answer:

lawyer [7]2 years ago

5 0

Answer:

Sample Respond: Let's assume it's equal to 14 cm. Substitute this value to the formula for circumference: C = 2 * π * R = 2 * π * 14 = 87.9646 cm . You can also use it to find the area of a circle: A = π * R² = π * 14² = 615.752 cm² . Finally, you can find the diameter - it is simply double the radius: D = 2 * R = 2 * 14 = 28 cm .

Step-by-step explanation:

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What is 13x+15= 11x -25 also expalin plz

kari74 [83]

$13x+15=11x-25 \\ \\ 13x-11x=-25-15 \\\\ 2x=-40 \\\\ \boxed{x=-\frac{40}{2}=-20}$

You pass the free terms wich don't contain 'x' in the othe part of the equal with changed signe ans the same for the terms wich contain x.

8 0

4 years ago

A game decreased in price by 2/3. After the reduction it was priced at £13. What was the original price of the game?

Archy [21]

Answer:

$x = 39$

Step-by-step explanation:

Based on the given conditions, write: $x=\frac{13}{1-\frac{2}{3}}$

Find common denominator and write numerators above common denominator: $x=\frac{\frac{13}{3-2} }{3}$

Calculate the sum or difference: $x=\frac{\frac{13}{1} }{3}$

Divide the fraction by multiplying its reciprocal: $x=13*3$

Calculate the product or quotient: $x=39$

Answer: $x=39$

5 0

2 years ago

Read 2 more answers

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :