Question

Consider functions f and g

Answer 1

Answer:

A

Step-by-step explanation:

$f(x) = \dfrac{x - 16}{x^2 + 6x - 40}$

$g(x) = \dfrac{1}{x + 10}$

$f(x) + g(x) = \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{1}{x + 10}$

$f(x) + g(x) = \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{(x - 4)}{(x + 10)(x - 4)}$

$f(x) + g(x) = \dfrac{x - 16 + x - 4}{x^2 + 6x - 40}$

$f(x) + g(x) = \dfrac{2x - 20}{x^2 + 6x - 40}$

Answer: A