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2 years ago

Consider functions f and g

Mathematics

1 answer:

alexdok [17]2 years ago

6 0

Answer:

Step-by-step explanation:

$f(x) = \dfrac{x - 16}{x^2 + 6x - 40}$

$g(x) = \dfrac{1}{x + 10}$

$f(x) + g(x) = \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{1}{x + 10}$

$f(x) + g(x) = \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{(x - 4)}{(x + 10)(x - 4)}$

$f(x) + g(x) = \dfrac{x - 16 + x - 4}{x^2 + 6x - 40}$

$f(x) + g(x) = \dfrac{2x - 20}{x^2 + 6x - 40}$

Answer: A

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