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nirvana33 [79]
3 years ago
15

Find YZ and WZ in rectangle WXYZ.

Mathematics
1 answer:
Anettt [7]3 years ago
6 0

Answer: WZ=10, YZ=15

Step-by-step explanation:

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g100num [7]
First it shows 33 points and ok
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3 years ago
The marketing firm in problem 1 has decided that age may also have an affect on attention span. They decide to assign the childr
WARRIOR [948]

Answer:a).it is an experiment

b).it is randomized.

c).The response variables are the various age groups;5--6,7--8,9--10

d)

Step-by-step explanation:

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3 years ago
What is the complete factorization of the polynomial below?
aksik [14]

Option A: (x+1)(x+3 i)(x-3 i) is the complete factorization of the polynomial x^{3} +x^{2} +9x+9

Explanation:

The polynomial is x^{3} +x^{2} +9x+9

Now, we shall find the complete factorization of the polynomial.

Let us group the common terms, we have,

\left(x^{3}+x^{2}\right)+(9 x+9)

Taking out the common terms,

x^{2} (x+1)+9(x+1)

Factor out x+1 from both the terms, we have,

\left(x^{2}+9\right)(x+1)=0

The term \left(x^{2}+9)\right. can be factored as

\begin{aligned}x^{2}+9 &=0 \\x^{2} &=-9 \\x &=\pm 3 i\end{aligned}  and \begin{aligned}x+1 &=0 \\x &=-1\end{aligned}

Thus, the roots are x=\pm 3 i and x=-1

These roots can be written as (x+1)(x+3 i)(x-3 i)

Thus, the complete factorization of the polynomial is (x+1)(x+3 i)(x-3 i)

8 0
3 years ago
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A dry Waller wants to order core board for a 15-story elevator shaft. Each floor uses 18.5 sheets.Calculate the number of boards
dybincka [34]

Answer:

305.25

Step-by-step explanation:

18.5 for one floor, multiply by 15 to get the amount for 15 floors: 18.5*15 = 277.5 sheets

We need to add 10% for waste, meaning 277.5 plus the waste: 1.1*277.5 = 305.25

6 0
2 years ago
How would you verify the trigonometric identity 2x = 2sinx cosx
dem82 [27]

Step-by-step explanation:

<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>sin2x</em><em>=</em><em>2</em><em>sinx</em><em> </em><em>.</em><em> </em><em>cosx</em>

<em>so</em><em>,</em><em> </em><em>let's</em><em> </em><em>begin</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>simple</em><em> </em><em>way</em><em>;</em><em> </em><em>by</em><em> </em><em>adding</em><em>,</em><em> </em><em>alright</em><em>:</em>

<em>sin2x</em><em>=</em><em> </em><em>sin</em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>as</em><em> </em><em>2</em><em>x</em><em>=</em><em>x</em><em>+</em><em>x</em><em>)</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>let's</em><em> </em><em>use</em><em> </em><em>compound</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>sin</em><em>,</em>

<em>so</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em>:</em>

<em>sin</em><em> </em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em>=</em><em> </em><em>sinx.cosx</em><em> </em><em>+</em><em> </em><em>cosx</em><em>.</em><em> </em><em>sinx</em><em> </em><em> </em><em> </em><em>(</em><em>as</em><em> </em><em>sin</em><em>(</em><em>A</em><em>+</em><em>B</em><em>)</em><em>=</em><em>sin</em><em> </em><em>A</em><em>.</em><em> </em><em>cosB</em><em> </em><em>+</em><em> </em><em>cosA</em><em> </em><em>.</em><em> </em><em>sinB</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>sin</em><em> </em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em>=</em><em>2</em><em>sinx</em><em>.</em><em>cosx</em><em> </em><em> </em><em>(</em><em>adding</em><em> </em><em>both</em><em>)</em><em>.</em>

<em>Therefore</em><em>, </em><em> </em><em>sin</em><em> </em><em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>2sinx</em><em>.</em><em> </em><em>cosx</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Read 2 more answers
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