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love history [14]
2 years ago
8

Find the length of PF

Mathematics
1 answer:
stepan [7]2 years ago
8 0

Answer: 6

Step-by-step explanation:

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It’s not C and I suck at math can someone plz help me on this plz and thx
Fittoniya [83]

Answer:

a

Step-by-step explanation:

The volume (V) of a cone is calculated as

V = πr²h ( r is the base radius and h the perpendicular height )

To calculate the height h use the right triangle formed by the radius and the inclined side.

Given diameter = 22, then r = 22 ÷ 2 = 11 cm

Using Pythagoras' identity on the right triangle, then

h² + 11² = 61² , that is

h² + 121 = 3721 ( subtract 121 from both sides )

h² = 3600 ( take the square root of both sides )

h = \sqrt{3600} = 60

Thus

V = π × 11² × 60

   = 3.14 × 121 × 60 ≈ 22796.4 cm³ → a

7 0
3 years ago
Monica has been saving her spare change. So far she has saved 40 coins for a total of $6.25. Some of the coins are quarters (25
neonofarm [45]

Answer:

10 quarters

40 dimes

Step-by-step explanation:

q + d = 40

25q + 10d = 625

25 > 10

q < d

25(10) = 250

10(40) = 400

$2.50 + $4.00 = $6.00

7 0
3 years ago
What is the x please answer me quick ​
nordsb [41]
First u do a squared +b squared =c squared aka pythagorean theorem then so u already have c squared so you would do 5x5=25 and 13x13=169 so then the equation would be 25+?=169 then do 169-25 which equals 144 and then do the square root of that which is 12 THE ANSWER IS 12
4 0
3 years ago
13 subtracted from a number x
Nesterboy [21]
13-x = 13- x 
theres is no answer for that x its a variable and 13 is a constant so is just 13-x
6 0
3 years ago
Read 2 more answers
Line L passes through the points (0, --3) and (6,9).<br> (a) Find the equation of line L.
valentina_108 [34]

Step-by-step explanation:

Given points are :

(0,\:-3)=(x_1,\:y_1) \:\&\: (6,\:9)=(x_2 ,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 }  = \frac{x -x_1 }{x_1 -x_2 }  \\  \\  \therefore \frac{y -( - 3)}{ -3  -9 }  = \frac{x -0 }{0 -6 }  \\  \\  \therefore \frac{y  + 3}{ -12}  = \frac{x  }{ -6 }  \\  \\  \therefore \frac{y  + 3}{ 2}  = \frac{x  }{1}  \\  \\  \therefore  \: y + 3 = 2x \\  \\  \huge \red{ \boxed{\therefore  \: 2x - y - 3 = 0}} \\ is \: the \: required \: equation \: of \: line.

5 0
3 years ago
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