Question

AB and BC and form a right angle at point B. If A = (-3, -1) and B = (4, 4), what is the equation of bc

Answer 1

Answer:

$y=\frac{-7}{5}x+\frac{48}{5}$ is equation of BC

Step-by-step explanation:

Given that AB and BC form a right angled triangle at point B.

i.e. BC is perpendicular to AB

Line AB contains two points (-3,-1) and (4,4)

Slope of AB =$\frac{y2-y1}{x2-x1} =\frac{4+1}{4+3} =\frac{5}{7}$

Slope of BC would be -1/slope of AB since AB and BC are perpendicular

Slope of BC =\frac{-7}{5}

Also we got a point on BC as B.

Use point slope formula

$y-y1=m(x-x1)\\y-4=\frac{-7}{5}(x-4)\\y=\frac{-7}{5}x+\frac{48}{5}$$y-y1=m(x-x1)\\y-4=\frac{-7}{5}(x-4)\\y=\frac{-7}{5}x+\frac{48}{5}$