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Alex_Xolod [135]
3 years ago
15

I need help asap!!!!!!!!!!!

Mathematics
2 answers:
sergeinik [125]3 years ago
5 0
First, we need to total the number of students that took the test:
1 student got between 1-20%
3 students got between 21-40%
5 students got between 41-60%
8 students got between 61-80%
8 students got between 81-100%
Therefore, the sum of the students is 1+3+5+8+8 = 25 students in total
There were 16 students who got a 61% or above, so the fraction of students that got a 61% or higher is 16/25. Convert this to a decimal, and we get 0.64. To convert from decimal to percent, multiply the decimal by 100%, and the final answer is 64% of students got a 61 or better on the exam.
Reil [10]3 years ago
3 0
Ur answer will be 8% and do u need me to explain 
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movie theater sold 5400 tickets yesterday of those, 3240 tickets were for Star Wars. what was the percentage it sold yesterday w
Gnesinka [82]
3240 star wars tickets divided into 5400 total tickets = .6 × 100 = 60%
May the Force be with you.
8 0
3 years ago
Matt started doing extra chores around the house and his allowance changed from $30 per week to $40 per week. What is the percen
slega [8]

Answer:

33.3%

Step-by-step explanation:

Let's say the percent change is x%. Then the equation is:

30 + x% * 30 = 40

Subtract 30 from both sides:

x% * 30 = 10

Divide by 30:

x% = 10/30 = 1/3

Remember that % simply means "out of 100", so:

x/100 = 1/3

Multiply both sides by 100:

x = (1/3) * 100 = 33.3%

3 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation below?
inysia [295]

The answer is C and D

First we must make one side of the equation zero, so we subtract 7 on both sides of the equation, making the equation 9x^2 - 6x - 6 = 0

Then we will use the quadratic formula to find the answers.

using the Quadratic Formula where:

a = 9, b = -6, and c = -6

and the formula is 6 +- \sqrt{6^{2} } -4 (9)(6) /2 (9)

6 0
3 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

#SPJ1

7 0
2 years ago
Calcula el perímetro (P) y área (A) del la siguiente figura
Dafna11 [192]
Are the link help us I search but they didn’t help
3 0
3 years ago
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