So car A travels Distance = 60 km/hr*(1+x)
Car B travels Distance = 75 km/hr(x)
Where x is the time in hours.
Those two equations are equal when on overtakes the other
so:
60 +60x = 75x
60=15x
x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.
For this case you can solve the problem by applying a simple rule of three in which we have
520 ---> 100%
800 ---> x
Clearing x we have
x = (800/520) * 100 = 154%
the percentage increase in cost was
154-100 = 54%
answer
the percentage increase in cost was 54%
Answer:
d. c. b. a.
Step-by-step explanation:
5x^2-4x+1 + -3x^2+x-3= 2x^2-3x-2
