Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Answer:
. We assume, that the number 260 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 260 is 100%, so we can write it down as 260=100%.
4. We know, that x is 6.75% of the output value, so we can write it down as x=6.75%.
5. Now we have two simple equations:
1) 260=100%
2) x=6.75%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
260/x=100%/6.75%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.75% of 260
260/x=100/6.75
(260/x)*x=(100/6.75)*x - we multiply both sides of the equation by x
260=14.814814814815*x - we divide both sides of the equation by (14.814814814815) to get x
260/14.814814814815=x
17.55=x
x=17.55
now we have:
6.75% of 260=17.55
Step-by-step explanation:
25 add them up Your welcome
Answer:
thanks
Step-by-step explanation:
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