The total revenue of the function is the product of the quantity and the price
The total revenue in terms of P is TR = 20P - 0.01P^2
<h3>How to determine the total revenue?</h3>
The demand and the cost functions are given as:
Quantity function, Q = 20 - 0.01P
Cost function, C(Q)=60+6Q
The total revenue is calculated as:
TR = Q * P
Substitute Q = 20 - 0.01P in the above equation
TR = P * [20 - 0.01P]
Evaluate the product
TR = 20P - 0.01P^2
Hence, the total revenue in terms of P is TR = 20P - 0.01P^2
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Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
Only this function is lineer.
Because it is arithmetic.
Answer:

Step-by-step explanation:
A sequence is defined by the recursive formula
If
then
for 
for 
for 
for 
Dividing <em>f(x)</em> by 2<em>x</em> + 5 leaves the same remainder as division by <em>x</em> + 5/2. By the remainder theorem, it is equal to <em>f </em>(-5/2), so the remainder here is
<em>f</em> (-5/2) = 8 (-5/2)³ + 4 (-5/2)² - 13 (-5/2) + 3 = -129/2