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Svetradugi [14.3K]
2 years ago
5

y- 1) The value, y, of a car x years after it is purchased is modeled by the function exponential function y = f(x), whose graph

is shown above Which statement about the car's value is true? A) Its initial value is B + A, and it will fall to a value of B B) its initial value is A, and it will fall to a value of B C) Its initial value is A and it will fall to a value of A-B ​
Mathematics
1 answer:
IgorLugansk [536]2 years ago
3 0

Given the exponential function y = f(x), a is the initial value and it will fall to a value of B

<h3>What is an exponential function?</h3>

An exponential function is given by:

y = abˣ

Where a is the initial value of y and b is the multiplication factor.

The value, y, of a car x years after it is purchased is modeled by the exponential function y = f(x), a is the initial value and it will fall to a value of B

Find out more on exponential function at: brainly.com/question/12940982

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Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
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n200080 [17]

Answer:

1

Step-by-step explanation:

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3 years ago
HELP ASAP!!! What is the slope of the line through (-1,-4) and (-6, -2)?
Mila [183]

Answer:

2/-5

Step-by-step explanation:

(-2) - (-4) = 2

(-6) - (-1) = -5

6 0
3 years ago
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7. What is 45% of 115? Show your work.
olchik [2.2K]
45/100 × 115 = 51.75...........
6 0
3 years ago
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What is 5 divided by 4/3
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3.75 as a decimal, 3 &3/4 as a fraction
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