A chemist has discovered<span> a </span>drug<span> that </span>blocks phosphoglucoisomerase<span>, an </span>enzyme<span> that </span>catalyzes<span> the</span>second reaction<span> in </span>glycolysis<span>. </span>He wants<span> to </span>use<span> the </span>drug<span> to </span>treat people<span> with </span>bacterial infections.However<span>, </span>he can't do<span> this </span>because _____<span>. human cells also perform </span>glycolysis<span>; the </span>drug<span> might also poison them. Most NADH ...</span>
A. The atmosphere
All the other examples are either elements or compounds, not mixtures. A mixture is a combination of elements that are not chemically or irreversibly conjoined so the atmosphere, made up of a variety of gases, would be a mixture.
Answer:
bond angles of 120 degrees.
Answer:
Rafflesia smell like roadkill others for only a few hours and while a few smaller species barely smell at all. And In short a parasitic life is heavily specialized biological requirements.
Explanation:
Answer:
1.7 mL
Explanation:
<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>
Step 1: Calculate [H⁺] in the dilute solution
We will use the following expresion.
pH = -log [H⁺]
[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M
Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.
Step 2: Calculate the volume of the concentrated HCl solution
We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂/C₁
V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL
