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pentagon [3]
3 years ago
14

Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO2 through the

Chemistry
1 answer:
gavmur [86]3 years ago
3 0

Answer:

2.48 × 10⁴ mol

Explanation:

Step 1: Write the balanced equation

2 CrO₄²⁻ + 3 SO₂ + 4 H⁺ ⇒ Cr₂(SO₄)₃ + 2 H₂O

Step 2: Calculate the reacting moles of CrO₄²⁻

3.00 × 10⁸ L of 5.50 × 10⁻² mM CrO₄²⁻ react. The reacting moles are:

3.00 × 10⁸ L × 5.50 × 10⁻² × 10⁻³ mol/L = 1.65 × 10⁴ mol

Step 3: Calculate the reacting moles of SO₂

The molar ratio of CrO₄²⁻ to SO₂ is 2:3. The reacting moles of SO₂ are 3/2 × 1.65 × 10⁴ mol = 2.48 × 10⁴ mol.

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A room is a cube that measures 4 meters in each dimension. If the temperature changes from 10 C to 30 C, and the pressure decrea
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Answer:

More air will enter the room since the volume of the room increases.

Explanation:

We'll begin by calculating the initial volume (V₁) of the room. This can be obtained as follow

Length (L) of room = 4 m

Initial volume (V₁) =..?

V₁ = L³

V₁ = 4³

V₁ = 64 m³

Next, we shall determine if there is an increase in the volume of the room or not. This can be obtained as follow:

Data obtained from the question include:

Initial volume (V₁) = 64 m³

Initial temperature (T₁) = 10 °C + 273 = 283 K

Final temperature (T₂) = 30 °C + 373 = 303 K

Initial pressure (P₁) = 760 mmHg

Final pressure (P₂) = 718 mmHg

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

760 × 64 / 283 = 718 × V₂ / 303

48640 / 283 = 718 × V₂ / 303

Cross multiply

283 × 718 × V₂ = 48640 × 303

203194 × V₂ = 14737920

Divide both side by 203194

V₂ = 14737920 / 203194

V₂ = 72.53 m³

SUMMARY

Initial volume (V₁) of room = 64 m³

Final volume (V₂) of room = 72.53 m³

From the calculations made above, we can see that the volume of the room increases from 64 m³ to 72.53 m³. Thus more air will enter the room since the volume of the room increases.

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