PLZ HELP WILL BRAINLIEST

What is the balanced chemical equation for Nitric acid with sodium carbonate

SOVA2 [1]

Answer:

Nitric acid reacts with sodium carbonateto form sodium nitrate, carbon dioxide and water. 2HNO3+Na2CO3→2NaNO3+CO2+H2O.

7 0

3 years ago

During studies of the reaction below,

Leni [432]

Answer: The percent yield of the nitrogen gas is 11.53 %.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NO:

Given mass of NO = 11.5 g

Molar mass of NO = 30 g/mol

Putting values in equation 1, we get:

$\text{Moles of NO}=\frac{11.5g}{30g/mol}=0.383mol$

For $N_2O_4$ :

Given mass of $N_2O_4$ = 102.1 g

Molar mass of $N_2O_4$ = 92 g/mol

Putting values in equation 1, we get:

$\text{Moles of }N_2O_4=\frac{102.1g}{92g/mol}=1.11mol$

For the given chemical reactions:

$2N_2H_4(l)+N_2O_4(l)\rightarrow 3N_2(g)+4H_2O(g)$ ......(2)

$N_2H_4(l)+2N_2O_4(l)\rightarrow 6NO(g)+2H_2O(g)$ .......(3)

Calculating the experimental yield of nitrogen gas:

By Stoichiometry of the reaction 3:

6 moles of NO is produced from 2 moles of $N_2O_4$

So, 0.383 moles of NO will be produced from = $\frac{2}{6}\times 0.383=0.128mol$ of $N_2O_4$

By Stoichiometry of the reaction 2:

1 mole of $N_2O_4$ produces 3 moles of nitrogen gas

So, 0.128 moles of $N_2O_4$ will produce = $\frac{3}{1}\times 0.128=0.384mol$ of nitrogen gas

Now, calculating the experimental yield of nitrogen gas by using equation 1, we get:

Moles of nitrogen gas = 0.384 moles

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

$0.384mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.384mol\times 28g/mol)=10.75g$

Calculating the theoretical yield of nitrogen gas:

By Stoichiometry of the reaction 2:

1 mole of $N_2O_4$ produces 3 moles of nitrogen gas

So, 1.11 moles of $N_2O_4$ will produce = $\frac{3}{1}\times 1.11=3.33mol$ of nitrogen gas

Now, calculating the theoretical yield of nitrogen gas by using equation 1, we get:

Moles of nitrogen gas = 3.33 moles

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

$3.33mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(3.33mol\times 28g/mol)=93.24g$

To calculate the percentage yield of nitrogen gas, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of nitrogen gas = 10.75 g

Theoretical yield of nitrogen gas = 93.24 g

Putting values in above equation, we get:

$\%\text{ yield of nitrogen gas}=\frac{10.75g}{93.24g}\times 100\\\\\% \text{yield of nitrogen gas}=11.53\%$

Hence, the percent yield of the nitrogen gas is 11.53 %.

7 0

3 years ago

If heat is added to a boiling liquid, what happens to the temperature of the liquid?

stealth61 [152]

Answer: C

Explanation:

Answer is "It does not change"

Hope this helps!

4 0

3 years ago

2.25 g/ml at 700mmHg, 200 C. Find molar mass of gas.

Harrizon [31]

Answer:

Molar mass = 94972.745 g/mol

Explanation:

Given data:

Density = 2.25 g/ml

Pressure = 700 mmHg

Temperature = 200°C

Molar mass = ?

Solution:

Density = 2.25 g/ml (2.25×1000 = 2250 g/L)

Pressure = 700 mmHg (700/760 = 0.92 atm)

Temperature = 200°C (200+273 = 473K)

Formula:

d = PM/RT

M = dRT/P

M = 2250 g/L × 0.0821 atm.L /mol.K × 473K / 0.92 atm

M = 87374.93 g/mol / 0.92

M = 94972.745 g/mol

6 0

3 years ago

The indicator methyl red has different molecular structures at high and low pH.

Novosadov [1.4K]

Answer:

a. True

Explanation:

Methyl red is an indicator widely used in quality control of oxides as Zinc oxide in the titration with sulfuric acid.

As is used in titrations of acid-base reactions the indicator change in colour. Is red when the pH < 4.4 (Acidic Solutions) and is yellow when pH > 6.2 (Neutral-Basic solutions).

A change in colour means the structure of the indicator is changing with pH. Thus, the answer is:

6 0

3 years ago