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4 years ago

Which statement is true about the climbers’ heights?

Mathematics

2 answers:

Irina-Kira [14]4 years ago

8 0

Answer:

Both climbers rested on the wall at a constant height for 2 minutes.

Step-by-step explanation:

Abby's climb begins with an increase. Then she rests from x = 4 to x = 6, which is 2 minutes. Then she increases again before she decreases.

Brynn's climb begins with an increase as well. Then she rests from x = 5 to x = 7, which is 2 minutes. Then she decreases.

The only correct statement is that both climbers rested on the wall at a constant height for 2 minutes.

Tresset [83]4 years ago

3 0

I think D.

They both rested for 2 minutes, however they did not rest at the same time, but it doesn't say they did that in the option choice.

Hope this helps!

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A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Arthur wants to buy an item that costs p dollars before tax. Using the Florida tax rate of 6%, write two different expressions t

REY [17]

The different expressions that represent the price of the item after tax will be p + 6/100p and p + 0.06p.

<h3>How to illustrate the expression?</h3>

The first expression will be:

= p + (6/100 × p)

= p + 6/100p

The second expression will be:

= p + (6% × p)

= p + 0.06p

It should be noted that both expressions are equal.

Learn more about tax on:

brainly.com/question/25783927

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8 0

1 year ago

Please answer <br><br> 8 + 9 x 1 x 2/2

12345 [234]

The answer would be 17.

7 0

3 years ago

Read 2 more answers

What shape has 3 straight sides other than a triangle?

iogann1982 [59]

None that is a real shape

6 0

3 years ago

Read 2 more answers

Here is an easy puzzle:

galina1969 [7]

The answer is
date
1 2 3 4 5 31
r1 r2 r3 r4 r5 . . . r31
1gm 2gms 3<span>gms 4gms 5gms . . . 31gms

r1+r2+ .... +r31= 31(31+1) /2=496gms (31 rings)

he only made 5 rings

31 rings----------> 496 gms
5 rings ------------> ? = 5 x496 / 31=80 gms

</span><span> the weights of those 5 rings was 80 gms</span>

4 0

4 years ago