Question

A sample of aluminum chloride (AIC1z) has a mass of 37.2 g.

Answer 1

The answers to your questions are as follows

A) The number of aluminium ions present = 1.62 * 10²³ ions

B) The number of chloride ions present = 9.86 * 10²³  ions

C) The mass of one unit of aluminium chloride = 133.34 grams

Given data :

mass of aluminium chloride = 37.2 g

molar mass of aluminium chloride = 133.34 g/mol

note : I mole of a molecule has 6 * 10²³ molecules  

Number of moles = mass / molar mass = 0.27 moles

Determine the number of aluminum ions and chloride ions present

A) aluminium ions present

moles of AlCl₃ * 6 * 10²³

= 0.27 * 6 * 10²³   = 1.62 * 10²³ ions

B) Chloride ions present

moles of AlCl₃ * 6 * 10²³  * 3

= 0.27 * 6 * 10²³ * 3

= 4.86 * 10²³ ions

C) The mass of one formula unit of aluminium chloride = 133.34 grams

Hence we can conclude that the answers to your question are as listed above.

Learn more about aluminium chloride : brainly.com/question/12849464