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Gwar [14]
3 years ago
12

This is earths science can anyone help me? I think I got it all wrong! I’m horrible with numbers.

Chemistry
1 answer:
Roman55 [17]3 years ago
4 0

Answer:

Crust percentage= 0.81%

Lithoshpere= 2.02%

Atmosphere= 3.63%

Mantle=  45.4%

Outer core= 45.72%

Inner core= 2.42%

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in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH2. In several experiments the rat
Inga [223]

Answer:

Ea= -175.45J

A= 3.5×10^14

k=3.64 ×10^14 s^2.

Explanation:

From

ln k= -(Ea/R) (1/T) + ln A

This is similar to the equation of a straight line:

y= mx + c

Where m= -(Ea/R)

c= ln A

y= ln k

a)

Therefore

21.10 3 104= -(Ea/8.314)

Ea=-( 21.10 3 104×8.314)

Ea= -175.45J

b) ln A= 33.5

A= e^33.5

A= 3.5×10^14

c)

k= Ae^-Ea/RT

k= 3.5×10^14 × e^ -(-175.45/8.314×531)

k = 3.64 ×10^14 s^2.

8 0
3 years ago
A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %
kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and y_{C-6} and y_{N_2} are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Q=-40036+(-672.21)=-40708.21J

Finally we convert this result to kJ:

Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ

Learn more:

  • brainly.com/question/25475410
  • brainly.com/question/12625048
6 0
2 years ago
What is the electron configuration of a chlorine ion in a compound of BeCl2?
mestny [16]
The  electronic  configuration  of  a   chlorine ion  in BeCl2  compound is

[2.8.8]^-  (answer  B)

chlorine  atom  gain  on electron form Be to  form  chloride ions
chlorine  atom  has  a  electronic   configuration of  2.8.7   and  it  gains one  electron  to  form  chloride ion  with  2.8.8  electronic  configuration
8 0
3 years ago
Read 2 more answers
Place the following in order of increasing acid strength. HBrO2 HBrO3 HBrO HBrO4 A) HBrO2
jarptica [38.1K]

Answer:

HBrO4 < HBrO3 < HBrO2 < HBrO

3 0
3 years ago
Your bedroom gets direct sunlight through a window during the hottest times of the day. you ask your mom to turn down the thermo
Kipish [7]

If you take your mom's advice, a. the room will be cooled by minimizing heat transfer by reflection.

The Sun is heating your room by its <em>radiation</em>.

The aluminium foil is shiny, so it reflects the Sun’s radiation back outside the window.

<em>Convection</em> is the transfer of heat caused by the air moving around in your room.

<em>Conduction</em> occurs only when a hot object is in contact with a cooler object.

5 0
3 years ago
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