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2 years ago

Drag each figure to show if it is similar to the figure shown or why it is not similar.

Mathematics

1 answer:

kiruha [24]2 years ago

8 0

<h2><u><em>1st one - not similar diff ratio</em></u></h2><h2><u><em></em></u></h2><h2><u><em>2nd- similar</em></u></h2><h2><u><em></em></u></h2><h2><u><em>3rd- not similar diff shape</em></u></h2><h2><u><em></em></u></h2><h2><u><em>4- not similar diff ratio</em></u></h2><h2><u><em></em></u></h2><h2><u><em>5- similar</em></u></h2><h2><u><em></em></u></h2><h2><u><em>6- not so sure but i would go w either not similar diff shape or similar</em></u></h2>

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What are two other negative integers that have the same sum as -2 and -5

Anestetic [448]

Answer:

-3,-4

-6,-1

Step-by-step explanation:

-3 + -4

-6 + -1

7 0

3 years ago

For every 15 students who run track, there are 7 students who play baseball. There are 112 more students

wolverine [178]

Answer:

There are 210 students running track and 98 students that play baseball.

Step-by-step explanation:

15*14= 210 and 7*14 = 98, 210 - 98 = 112. If this was correct feel free to mark me as brainiest :)

4 0

4 years ago

Read 2 more answers

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

3 years ago

Which expression is equivalent to (x^4/3x^2/3)^1/3

stellarik [79]

Answer:

x 8/9

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the equation of the trend line?<br> Enter your answers in the boxes.<br><br> K = _J +_

MrRissso [65]

The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0

Thus, the equation of the trend line, in variables K and J, is

K = 2J + 28

8 0

3 years ago