Hello :
f'(7) = the slope of the tangent line : let A(7,4) B(0,3)<span>
<span>the slope is : (YB - YA)/(XB -XA)= (3-4)/(0-7) = -1/-7 = 1/7=f'(7)
the equation of the tangent line is :
y-3 = 1/7 (x-0)
y = (1/7)x+3
the line tangent and the graph of : f </span></span><span>passes through the point A(7, 4)
x= 7 y=4 so : f(7) =4</span>
The <em><u>correct answer</u></em> is:
AAS
Explanation:
AAS stands for "angle-angle-side." This states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of another triangle, then the triangles are congruent.
In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with. Throughout the proof, we find that ∠ABC ≅ ∠DCB. We also have that CB is congruent to itself. This is two angles and a side not included, so this is AAS.
The series 1022,1032,1042,1052....
a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term
Sn= a+(n-1)d
= 1022+(5-1)10
= 1022+40
= 1062
Next house will have 1062 as number.
Answer:
Step-by-step explanation:
The diameter of a circle is twice the radius, so the statement is false.
Answer: 3t²(2st⁷ - s⁶ - 2t⁵)
<u>Step-by-step explanation:</u>
5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷ <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>
= 6st⁹ - 3s⁶t² - 6t⁷ <em>next, factor out the GCF of 3t²</em>
= 3t²(2st⁷ - s⁶ - 2t⁵)
