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2 years ago

I need help with Function Operations

Mathematics

1 answer:

natita [175]2 years ago

7 0

Answer: 189

All Steps and Information Found in Image.

Hope This Helped!

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A bag contains red, green, and yellow marbles. The probability of selecting a red marble is 35%. What is the probability of not

KonstantinChe [14]

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

6 0

2 years ago

Q # 2 Graph TWX and it's image after a rotation of 90° counterclockwise about the origen

const2013 [10]

For a rotation of 90o: (x, y) ⇒ (–y, x)
T(3,4) ⇒⇒⇒ T'(-4,3)
W(-2,-1) ⇒⇒⇒ W'(1,-2)
x(-3,3) ⇒⇒⇒ x'(-3,-3)

see the attached figure

6 0

3 years ago

WHOEVER GETS THIS RIGHT IN 3 MINUTES GETS THE BRAINLIEST!! Four times the sum of a number and 15 is at least 120. Let x represen

larisa [96]

Hey there!

Let's call this "number" x. We want four times the sum of this number and 15 to equal at least 120.

Therefore, we want this number times four plus fifteen to be greater than or equal to 120. We have:

$4(x+15)\geq 120$

Distribute:

$4x + 60 \geq 120$

Subtract:

$4x\geq 60$

Divide:

$x\geq 15$

Your answer is C.

Hope this helps!

7 0

3 years ago

How many sides does a regular polygon have if its interior angles A. 156 B. 162

Kruka [31]

I) 156 degrees
The exterior angle is 180-156
=24
The number of sides= $\frac{360}{24}$
The number of sides= 15 sides

ii) 162 degrees
The exterior angle= 180-162
=18
The number of sides= $\frac{360}{18}$
= 20 sides

4 0

3 years ago

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago