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2 years ago

Please help with angle addition

Mathematics

1 answer:

KonstantinChe [14]2 years ago

4 0

Answer:

m∠1 = 89°

Step-by-step explanation:

Since m∠2 is a part of ∠GFH, he can do the following.

∠GFH - m∠2 = m∠1

133° - 44° = 89°

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Find the difference.<br><br> 6rs – (-2rs)

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3 years ago

3. Write in algebra form 4 units to the right and 3 anit down

viva [34]

Answer:

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2 years ago

A cartographer wants to create a map of Seattle. He has designed key/legend for the map indicating that 1 cm equals 2 miles. If

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3 years ago

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Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .

The number of fish tripled in the first year. This means that $P(1) = 3P(0) = 3(80) = 240$ .

Using the equation for P(1), that is, P(t) when $t = 1$ , we find the value of r.

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

$240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}$

$280*(2000 + 80(e^{r} - 1)) = 160000e^{r}$

$280*(2000 + 80e^{r} - 80) = 160000e^{r}$

$280*(1920 + 80e^{r}) = 160000e^{r}$

$537600 + 22400e^{r} = 160000e^{r}$

$137600e^{r} = 537600$

$e^{r} = \frac{537600}{137600}$

$e^{r} = 3.91$

Applying ln to both sides.

$\ln{e^{r}} = \ln{3.91}$

$r = 1.36$

This means that the expression for the size of the population after t years is:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

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3 years ago

Q23. Look at the image

alisha [4.7K]

Answer:

B. First term = 5, Common difference = -3

Step-by-step explanation:

The first term is f(1) = 8 - 3(1) = 8 - 3 = 5.

The common difference is the coefficient of n. Another way to see this is to compute the second term, f(2) = 8 - 3(2) = 8 - 6 = 2. The second term is 3 less than the first. The common difference is -3.

The sequence goes 5, 2, -1, -4, ...

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3 years ago