<u>Restando la cantidad utilizada de el total</u>, tiene-se que 7470 clavos le quedan.
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- En total, para la construcción, Samuel compró 7,943 clavos.
- De toda esta cantidad, 473 fueron utilizadas.
- La cantidad de clavos que le quedan es la <u>subtracción da cantidad total por la utilizada</u>, o sea, 7943 restado de 473.

Le quedan 7470 clavos.
Un problema similar es dado en brainly.com/question/24554492
 
        
             
        
        
        
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean  and standard deviation
 and standard deviation  , the zscore of a measure X is given by:
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.




Weights of at least 340.1 are in the highest 20%.
 
        
             
        
        
        
It's False; an octagon has 8 vertices. When you remove the starting vertex and the two adjacent vertices we're left with 5 possible diagonals
        
             
        
        
        
It can help because 9×4 =36, and 9×8=72. if you divide 72 by 2 you get 36 which is the answer to 9 ×4. basically because nine is the same in both problems you are multiplying by 4 (and you know 4 is half of 8) you can assume that multiplying the sum of 4 and 9 that you will get the sum of 8 and 9.