Answer:
C The launcher will fall off the platform and land D/2 to the left of the platform because the launcher is twice the mass of the ball.
Explanation:
The figure is missing: you can find it in attachment.
We can apply the law of conservation of momentum to check that the launcher will leave the platform with a speed which is half the speed of the ball. In fact, the total initial momentum is zero:
while the total final momentum is:
where
is the mass of the launcher
is the mass of the ball
is the velocity of the launcher
is the velocity of the ball
Since the total momentum must be conserved, , so
Therefore we find
which means that the launcher leaves the platform with a velocity which is half that of the ball, and in the opposite direction (to the left).
Since the distance covered by both the ball and the launcher only depends on their horizontal velocity, this also means that the launcher will cover half the distance covered by the ball before reaching the ground: therefore, since the ball covers a distance of D, the launcher will cover a distance of D/2.
Answer:
mole fraction of toluene 0.53
Explanation:
given data:
vapor pressure of benzene = 160 torr
vapor pressure of toluene = 50 torr
mole of benzene = 3.8 mol
mole of toluene = 5.7 mol
calculate total pressure
here total pressure = mole fraction of toluene x vapour pressure of toluene + mole fraction of benzene x vapor pressure of benzene
mole fraction of toluene
mole fraction of Benzene
= 94 torr
we have mole fraction of toluene in vapor phase =\frac{50}{94} =
= 0.53 (ans)
Answer: 592.37m
Explanation:
Person D is the blue line.
The total displacement is equal to the difference between the final position and the initial position, if the initial position is (0,0) we have that he first goes down two blocks, then right 6 blocks. then up 4 blocks, then left 1 block.
Now i will considerate that the positive x-axis is to the right and the positive y-axis is upwards.
Then the new position will be, if B is a block:
P =(6*B - 1*B, -2*B + 4*B) = (5*B, 2*B)
And we know that B = 110m
P = (550m, 220m)
Now, then the displacement will be equal to the magnitude of our vector, (because the difference between P and the initial position is equal to P, as the initial position is (0,0)) this is:
P = √(550^2 + 220^2) = 592.37m