Answer:
282 m
Explanation:
Given:
v₀ = 20.1 m/s
v = 33.2 m/s
t = 10.6 s
Find: Δx
Δx = ½ (v + v₀) t
Δx = ½ (33.2 m/s + 20.1 m/s) (10.6 s)
Δx ≈ 282 m
To solve this problem we use the general kinetic equations.
We need to know the time it takes for the car to reach 130 meters.
In this way we have to:

Where
= initial position
= initial velocity
= acceleration
= time
= position as a function of time

.
We use the quadratic formula to solve the equation.

t = 6.63 s and t = -17.1 s
We take the positive solution. This means that the car takes 6.63 s to reach 130 meters.
Then we use the following equation to find the final velocity:

Where:
= final speed
The final speed of the car is 27.25 m/s
83 km/h * 2.5 hours (3:30 - 1:00) = 207.5 km
207.5 km - 15 km = 192.5 km
Answer:
V₂=4.57 x 10³ L
Explanation:
Given that
V₁= 2.88 x 10³ L
P₁=722 mm Hg
T₁ = 19°C
T₁ =292 K
P₂=339 mm Hg
T₂= - 55°C
T₂=218 K
Lets take final volume = V₂
We know that ideal gas equation
PV = m R T
By applying mass conservation


V₂=4.57 x 10³ L
Therefore volume will be 4.57 x 10³ L
Answer:
Acceleration
Explanation:
Acceleration has units of length per time squared.