Answer:
Dear Kaleb
Answer to your query is provided below
Acceleration of the vehicle is 12m/s^2
Explanation:
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Answer
given,
Mass of the solid sphere = 1800 Kg
radius of the sphere,R = 5 m
mass of the small sphere, m = 2.30 Kg
when the Point is outside the sphere the Force between them is equal to
when r>R
When Point is inside the Sphere
when r<R
where r is the distance where the point mass is placed form the center
Now Force calculation
a) r = 5.05 m
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F = 1.082 x 10⁻⁸ N
b) r = 2.65 m
We can calculate the length of each spring by using the relationship:
where
F is the force applied to the spring
k is the spring constant
x is the length of the spring (measured with respect to its rest position)
Re-arranging the equation, we have
The force applied to both spring is F=60 N. Spring A has spring constant of k=4 N/m, therefore its length with respect to its rest position is
Spring B has spring constant of k=5 N/m, so its length with respect to its rest position is
Therefore, the correct answer is
<span>D.Spring A is 3 m longer than spring B because 15 – 12 = 3.</span>
where
F is the force applied to the spring
k is the spring constant
x is the length of the spring (measured with respect to its rest position)
Re-arranging the equation, we have
The force applied to both spring is F=60 N. Spring A has spring constant of k=4 N/m, therefore its length with respect to its rest position is
Spring B has spring constant of k=5 N/m, so its length with respect to its rest position is
Therefore, the correct answer is
<span>D.Spring A is 3 m longer than spring B because 15 – 12 = 3.</span>