Answer:
Yes, the mean age of onset of anorexia nervosa in women has decreased.
Step-by-step explanation:
When constructing confidence intervals, remember the acronym PANIC.
P (p definitions)
let p = the newly recorded mean age of the onset of anorexia nervosa in women
A (assumptions)
There is no evidence in the problem that the women were randomly or independently selected, but we will proceed as if they were. It is reasonable to assume that there are over 200 women in the world, so this sample is less than 10% of the total population. We will assume that the onset of anorexia nervosa has a fairly normal distribution, so the smaller sample size will suffice.
N (name the test)
Because the required conditions are met, we can construct a 95% confidence interval.
I (interval)
Interval = 
Interval = 
Interval = 
Interval = (13.5874, 14.9126)
C (conclusion)
Based on this interval, I am 95% confident that the true mean age of the onset of anorexia nervosa in women is between 13.58 and 14.91 years. Since 15 is not included in this interval, I believe that the mean age of the onset of anorexia nervosa in women has decreased.
Answer:
angle GFD and angle EFD
Step-by-step explanation:
angle GFD and angle EFD because it is on a straight line.
Answer:
Hi,
Step-by-step explanation:
So it says the first six months average is 75mm. Total÷Amount =Average so Average x Amount = Total The first six months is 75 so 75x6= 470. The last six months is 15 so 15x6=90. In total, 470+90=560. We need to find the new average so we do 560÷(6+6)= 46.666666… so we round it to 46.67.
I. hope you find this helpful.
Answer:
In ΔOPQ, \text{m}\angle O = (6x-14)^{\circ}
Answer:
The answer is 4.8cm³
Step-by-step explanation:
First, you have to find the length of BC using trigonometric identities :
sinθ = oppo/hypo
cosθ = adj/hypo
tanθ = oppo/adj
Given that ∠BAC = 45° so you can use tanθ to find length of AB :
tan45° = BC/3.6
BC = 3.6×(tan45°)
= 3.6cm
Now, find the volume of pyramid using V = (1/3)×base area×h :
h = BC = 3.6cm
base area = 2×2
= 4cm²
V = (1/3)×4×3.6
= 4.8cm³