Well, part of 'velocity' is the direction of the motion, and the graph doesn't give us any information about the direction. So the best we'll be able to do is find the average SPEED of the car.
On a distance/time graph, the speed is just the slope of the line. Since this graph is a straight line, it doesn't matter which points along the line you choose ... the answer will always be the same.
Average speed = (distance covered) / (time to cover the distance)
Let's use the ends of the line ... the origin, and the point at the top.
On the left side of the graph, we see the label 'Distance (m)', and I don't know what 'm' stands for. It could be 'miles' or 'meters'.
Anyway, the point at the top of the line shows that the car covered a distance of 25.0 'm' in 10.0 s of time.
Average speed = (25 m) / (10 s)
Average speed = (25/10) m/s
(I'm pretty sure that 'm' means 'meters' and 's' means 'seconds'.)
Explanation:
FOR PARALLEL: the formulas are÷
1/Rt = 1/R1+ 1/R2 + 1/R3
Vt= v1 = v2 = v3
It= i1+ i2+ i3
Try this suggested solution; note, the answers are underlined with red colour.
If the ball weighs 5 newtons, then that's the force of gravity that
attracts it to the center of the Earth. The force only depends on
the mass of the ball and its distance from the center of the Earth.
The force of gravity doesn't care whether the ball is moving or at
rest. It doesn't change significantly until the ball moves to some
significant distance off the Earth's surface, which isn't happening
if it's tossed by a human being.
So we have a downward force of 5 newtons on the ball at all times.
In order to find the net force on it, we have to identify any other
forces besides gravity that are also acting on it.
If the ball were moving through the air, then there would be a force
of air resistance on it, acting opposite to its motion. But when it's
at its maximum height, in the process of turning around from rising
to falling, there's an instant when it's not moving through the air at all,
so gravity is the only force acting on it. At that moment, the net force
on the ball is 5.0 newtons downward.