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BigorU [14]
2 years ago
13

Which force counteracts motion whenever two surfaces come into contact?.

Physics
1 answer:
stellarik [79]2 years ago
3 0

Answer:

crush

Explanation:

because the body come into contact

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miskamm [114]

Time = (distance covered) / (speed)

Time = (224 mi) / (56 mi/hr)

<em>Time = 4 hours</em>

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3 years ago
What factors determine the presence of electrical energy?
luda_lava [24]
One of them would be power source.
8 0
3 years ago
a train has an initial velocity of 30 m/s. If the train accelerates uniformly at a rate of 6.3 m/s ^ for 2.8 seconds what is the
Annette [7]

T

Answer:

the velocity is a second final to initial velocity of 39

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2 years ago
Please help me asap ​
ddd [48]

Answer:

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8 0
3 years ago
An oscillator consists of a block of mass 0.628 kg connected to a spring. When set into oscillation with amplitude 27 cm, the os
oksian1 [2.3K]

Answer:

T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N

Explanation:

a.)

Period: It is already given in the question "oscillator repeats its motion every 0.372 s".

So T=0.372 s

b)

frequency= f = 1/ T

f = 1/ 0.372

f=2.7 Hz

c).

Angular frequency= w= 2πf

w= 2*π*2.7

w=16.9 rad/s

d)

Spring Constant:

As w=\sqrt{k/m}

⇒w²= k/m

⇒k= m*w²

⇒k= 0.628 * 16.9² N/m

⇒k=179.2 N/m

e)

The mass will have maximum speed when it passes through the mean position.

At mean position

Maximum elastic potential energy = Maximum kinetic energy

1/2 k A² = 1/2 m v²    ( A is amplitude of oscillation)

⇒ v=\sqrt{k A^2/m}

⇒ v= \sqrt{179.2 * 0.27/ 0.628}\

⇒ v= 8.78 m/s

f)

Maximum force will be exerted on the block when it is at maximum distance.

F= k* A   ( A is amplitude of oscillation)

F= 179.2 * 0.27 N

F= 48.4 N

5 0
3 years ago
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