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Anuta_ua [19.1K]
3 years ago
10

During a particular thunderstorm, the electric potential between a cloud and the ground is vcloud - vground = 1.5 x 108 v, with

the cloud being at the higher potential. what is the change in an electron's potential energy when the electron moves from the ground to the cloud?
Physics
1 answer:
lord [1]3 years ago
5 0
Voltage is potential energy per coulomb (J/C). So use the voltage and charge on an electron to get E=V•Q=1.5e8•1.602e-19=2.4e-11J
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Which phrases describe all the outer planets’ motion? Select two options.
AysviL [449]

Answer:

Fast rotation

Slow revolution

Explanation:

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They are gaseous. There  period of revolution is larger than the inner planets which means that they have slow revolution about the Sun. One day on the outer planets is smaller than the inner planets which means they have fast rotation.

For example, Jupiter has revolves around sun in 11.86 Earth years and rotates about axis in 9.8 Earth hours. Uranus revolves around sun in 84 Earth years and rotates on its axis 17.9 Earth hours.

8 0
3 years ago
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Why is it incorrect to say heavy objects sink in water?
lesya [120]
It is incorrect to say heavy objects sink in water because based on the density of the water it can actually cause the "heavy object" to float, out weighing it.
8 0
3 years ago
When a bicycle coasts uphill, it moves slower and slower as it climbs. Why?
astra-53 [7]

Letter B because it is gaining more potential energy as it SLOWLY climbs up the hill.

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6 0
3 years ago
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Mary starts at the edge of a circular platform that is slowly rotating on a frictionless axle. She then walks towards the opposi
bulgar [2K]

Answer:

Explanation:

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According to the relationship

w = v/r where

w is the angular velocity

r is the radius

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Initially, before Mary starts, her linear speed is zero and her angular velocity is also zero. As she move towards the opposite edge, she is covering a distance of radius r. According to the formula, increase in radius will leads to decrease in her angular velocity and vice versa. As Mary starts moving towards the centre of the circular path, her angular velocity increases, at the centre of the platform, her angular velocity is at maximum at this point. As she moves further from the center to the other edge, her angular velocity decreases due to increase in distance covered across the circular path.

6 0
3 years ago
15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?
____ [38]

A pendulum is not a wave.

-- A pendulum doesn't have a 'wavelength'.

-- There's no way to define how many of its "waves" pass a point
every second.

--  Whatever you say is the speed of the pendulum, that speed
can only be true at one or two points in the pendulum's swing,
and it's different everywhere else in the swing.

-- The frequency of a pendulum depends only on the length
of the string from which it hangs.


If you take the given information and try to apply wave motion to it:

             Wave speed = (wavelength) x (frequency)

             Frequency  =  (speed) / (wavelength) ,

you would end up with

             Frequency = (30 meter/sec) / (0.35 meter) = 85.7 Hz

Have you ever seen anything that could be described as
a pendulum, swinging or even wiggling back and forth
85 times every second ? ! ?     That's pretty absurd. 

This math is not applicable to the pendulum.

6 0
3 years ago
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