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Anuta_ua [19.1K]
3 years ago
10

During a particular thunderstorm, the electric potential between a cloud and the ground is vcloud - vground = 1.5 x 108 v, with

the cloud being at the higher potential. what is the change in an electron's potential energy when the electron moves from the ground to the cloud?
Physics
1 answer:
lord [1]3 years ago
5 0
Voltage is potential energy per coulomb (J/C). So use the voltage and charge on an electron to get E=V•Q=1.5e8•1.602e-19=2.4e-11J
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10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

8 0
3 years ago
When frequency is decreased what happens to the amplitude?
guajiro [1.7K]

Answer:

it increases the amplitude of the wave as it propagates.

Explanation:

7 0
2 years ago
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Consider a block of mass m attached to two springs, one on the left with spring constant k1 and one on the right with spring con
Andrew [12]

Answer:

T= 2\pi\times sqrt(m/(k1+k2))

Explanation:

When the block is displaced by x units

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two springs are connected parallel

F =-k_1x - k_2x

Writing Newtons second law, F = ma

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-k_1x - k_2x = mx''

a= x" ( differentiating x w.r.t time twice)

x''+(k_1/m + k_2/m) x=0

this the standard form of equation of oscillation spring mass system

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since,  Period T=2\pi\sqrt{\frac{m}{K_{eq.}} }

therefore,

T= 2\pi\times sqrt(m/(k1+k2))

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