3 years ago

A train starts at v=10m/s and accelerates at 1m/s2 for 5s. Its final speed is *

Physics

1 answer:

ad-work [718]3 years ago

3 0

Answer:

D) 15 m/s

Explanation:

v = u + at

v = 10 m/s + 1 m/s²(5 s)

v = 15 m/s

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Explanation:

Given that,

A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km.

We need to find his displacement from the starting position.

We know that,

Displacement = shortest path covered

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For direction,

$\theta=\tan^{-1}(\dfrac{d_y}{d_x})\\\\\theta=\tan^{-1}(\dfrac{12}{9})\\\\= $$53.13^{\circ}$

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$\text{Vector product}=172.66\ m^2$

Explanation:

Given that,

The magnitude of vector A, $|A|=13\ m$

The magnitude of vector B, $|B|=16\ m$

Scalar product of A and B, $A{\cdot} B=116\ m^2$

The formula for the scalar product is given by :

$A{\cdot} B=|A||B|\cos\theta$

Where, $\theta$ is the angle between A and B.

$\cos\theta=\dfrac{116}{13\times 16}\\\\\theta=\cos^{-1}\left(0.5576\right)\\\\\theta=56.11^{\circ}$

The formula for the vector product is given by :

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