Answer:
40.92 m/s
Explanation:
The computation is shown below:
Ek = 1 ÷2mv²...............................(1)
v = √(2Ek/m).......................... (2)
Here EK denotes kinetic energy
m denotes mass
v denotes velocity
Given that
m = 0.25kg and Ek = 209.3J
So,
v = √(2×209.3 ÷0.25)
= √1674.4
= 40.92 m/s
Meters would be the best way to record the length
The answer is "B" - If there are no windows then there will be no light coming in, and therefore you don't have to worry about what time of day you do the experiment at.
Answer:
y = 67.6 feet, y = 114.4/ (22 - 3t)
Explanation:
For this exercise let's use that light travels in a straight line and some trigonometric relationships, the symbols are in the attached diagram
Large triangle Projector up to the screen
tan θ = y / L
For the small triangle. Projector up to the person
tan θ = y₀ / (L-d)
The angle is the same, so we equate the two equations
y₀ / (L -d) = y / L
y = y₀ L / (L-d)
The distance from the screen (d), we look for it with kinematics
v = d / t
d = v t
we replace
y = y₀ L / (L - v t)
y = 5.2 22 / (22 - 3 t)
y = 114.4 (22 - 3t)⁻¹
This is the equation of the shadow height change as a function of time
For the suggested distance the shadow has a height of
y = 114.4 / (22-13)
y = 67.6 feet
Answer:
it gets brighter because the volta increases