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Angelina_Jolie [31]
3 years ago
10

11 points!!! what happened when glucose reacts with air? ​

Physics
1 answer:
ella [17]3 years ago
3 0
When glucose (C6H12O6) reacts with oxygen, carbon dioxide and water are produced. The reaction produces moles of carbon dioxide and moles of water.
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Which statement describes a property of a proton?
lesantik [10]

Answer:

They have no charge and are present in the nucleus of an atom. They have a negative charge and travel around the nucleus of an atom. They have a positive charge and travel around the nucleus of an atom

Explanation:

7 0
3 years ago
A (nonconstant) harmonic function takes its maximum value and its minimum value
AURORKA [14]

Answer:

Explanation:

Consider that F (any function) <0 .

u(x,y) is a coontinuous function in the closed interval or region R.

Let us consider a point (p,q) that is inside the region and it is a maximum point.

Then it should be must

uxx (p,q) <0 where uxx means double differentiation

and uy(p,q) >0

Since ux(p,q) = 0 = uy(p,q) where ux and uy means single differentiation with respect to x and y respectively.

Say, Maximum limits of the region is T

therefore q<T

then uy (p,q) = 0 if q<T

if q = T then

point (p,q) = (p,T) will be on the boundary of R then we claim that

uy(p,q) >0

Similarly for the minimum also it will work

3 0
3 years ago
Waves are created on the surface of water when we drop a stone into it. Similarly you must have seen the waves generated on a st
antoniya [11.8K]

Answer:

gdfhf

Explanation:

  1. jjjjcjbwwfbooob#kkkkkkkki!vdvdiiiiiibl#dnqljuwhgeyehrhrygrgdyhehegegeggegegegeegegegevegwgegegegsjkegsygegdydheheyrteeeudgeedyeyrf
5 0
3 years ago
What is the maximum acceleration of a platform that oscillates at amplitude 4.70 cm and frequency 6.50 Hz?
mylen [45]

Answer:

78.315 m/s²

Explanation:

Amplitude, A = 4.70 cm = 0.047 m

Frequency, f = 6.50 Hz

Angular frequency, ω = 2 π f = 2 x 3.14 x 6.50 = 40.82 rad/s

Maximum acceleration, a = ω² A

a = 40.82 x 40.82 x 0.047

a = 78.315 m/s²

8 0
4 years ago
When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, its frequency is 12Hz. When
anzhelika [568]

Answer:

Explanation:

Given

When m_1 mass is attached to the spring its frequency is f_1=12\ Hz

when another mass m_2 is attached to m_1 , frequency changes to f_2=4\ Hz

frequency of spring mass system is given by

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

for m_1

f_1=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}

12=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}-----1

for m_1 and m_2

f_2=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}

4=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}----2

divide 1 and 2

3=\sqrt{\frac{m_1+m_2}{m_1}}

squaring

9=1+\frac{m_2}{m_1}

\frac{m_2}{m_1}=8

   

8 0
3 years ago
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