<em><u>throwing a ball up initially has a lot of kinetic energy because it is moving upwards ( kinetic energy is energy which a body possesses by virtue of being in motion.) this all then get converted to gravitational potential energy, and for a moment it is stationary before it begins to fall again. by the time it has returned again, all the gravitational potential energy has turned back into kinetic.</u></em>
Answer:
The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.
Explanation:
Distance refers to the length between any two points in space, while displacement refers to the distance from a start position to an end position regardless of the path.
In other words, distance refers to how much space an object travels during its movement; is the quantity moved. It is also said to be the sum of the distances traveled. The distance traveled by a mobile is the length of its trajectory and it is a scalar quantity. In this case, the distance is calculated as:
1850 m + 1200 m= 3,050 m
Displacement refers to the distance and direction of the final position from the initial position of an object. The displacement effected is a vector quantity. The vector representing the displacement has its origin in the initial position, its end in the final position, and its module is the distance in a straight line between the initial and final positions. That is, when expressing the displacement it is done in terms of the magnitude with its respective unit of measurement and the direction because the displacement is a vector type quantity. Mathematically, the displacement (Δd) is calculated as:
Δd= df - di
where df is the final position and di is the initial position of the object.
In this case, the displacement is calculated as:
1850 m - 1200 m= 650 m
Since the distance to the north is greater, the direction of travel will be to the north.
<u><em>The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.</em></u>
Answer:
.
Explanation:
Let 
denote the absolute temperature of this object.
Calculate the value of before and after heating:
.
.
By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to 
.
Ratio between the absolute temperature of this object before and after heating:
.
Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:
.
I’m lost at this question, sorry but I would’ve help !
Which conditions I think you have place an incorrect image?
