1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inessss [21]
3 years ago
15

The drag coefficient of a car at the design conditions of 1 atm, 25°c, and 90 km/h is to be determined experimentally in a large

wind tunnel in a full-scale test. the height and width of the car are 1.25 m and 1.65 m, respectively. if the horizontal force acting on the car is measured to be 230 n, determine the total drag coefficient of this car. take the density of air at 1 atm and 25°c as ρ = 1.164 kg/m3. (round the final answer to two decimal places.)
Physics
1 answer:
Anvisha [2.4K]3 years ago
8 0
Velocity = 90 km/h = 25 m/s

Drag coefficient, Cd = 2D/Density of air*Frontal area*sqr. velocity

Substituting,

Cd = (2*230)/(1.164*1.25*1.65*25^2) = 0.3066
You might be interested in
What happens when you place two magnets close together?
seropon [69]
They repel.




Hope this helped
4 0
3 years ago
Practice with Density
bekas [8.4K]

Answer:

5.7 g/cm3

Explanation:

7 0
3 years ago
Read 2 more answers
You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa
MariettaO [177]

(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

W=mg\Delta h

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and \Delta h=1.8 m is the variation of height. Substituting the numbers into the formula, we find

W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J


(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

W=Fd

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.


(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

W=mg \Delta h=(3.4 kg)(9.81 m/s^2)(-1.8 m)=-60.0 J

8 0
3 years ago
A figure shows a vertically moving block on the end of a cord. The graph next to the figure gives the vertical velocity componen
Sergio [31]
It should be 2/9/10 in functional form
3 0
3 years ago
Which of the following statements about psychodynamic perspective is not true?
Free_Kalibri [48]
There are NO true statements on that list of choices.
3 0
3 years ago
Other questions:
  • A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a s
    15·1 answer
  • When the amplitude of a wave triples, the intensity changes by a factor of [blank](1/3,1/9,3,9)
    8·2 answers
  • An object of mass m slides down an incline with angle 0.
    6·2 answers
  • How do scientists determine where an earthquake starts?
    12·2 answers
  • What hormone is not related to stress
    7·1 answer
  • How do wavelength and wave period relate to a wave's speed
    5·1 answer
  • An energy-efficient water heater draws 4 amps in a 220-volt circuit. It costs $75 more that a standard water heater that draws 1
    13·1 answer
  • <img src="https://tex.z-dn.net/?f=%5Chuge%20%5Cfbox%20%5Cpink%20%7Bq%7D%5Chuge%20%5Cfbox%20%5Cgreen%20%7B%CF%85%7D%5Chuge%20%5Cf
    9·2 answers
  • Please refer to the picture
    14·1 answer
  • My dad gifted me a calculator. I have observed that very small cells are used in a calculator. What are these cells called and w
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!