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inessss [21]
3 years ago
15

The drag coefficient of a car at the design conditions of 1 atm, 25°c, and 90 km/h is to be determined experimentally in a large

wind tunnel in a full-scale test. the height and width of the car are 1.25 m and 1.65 m, respectively. if the horizontal force acting on the car is measured to be 230 n, determine the total drag coefficient of this car. take the density of air at 1 atm and 25°c as ρ = 1.164 kg/m3. (round the final answer to two decimal places.)
Physics
1 answer:
Anvisha [2.4K]3 years ago
8 0
Velocity = 90 km/h = 25 m/s

Drag coefficient, Cd = 2D/Density of air*Frontal area*sqr. velocity

Substituting,

Cd = (2*230)/(1.164*1.25*1.65*25^2) = 0.3066
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The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

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From Newton's second law;

\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\

From the graph;

\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m

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Hence, the resulting change in momentum of the system will be +18.6 Ns.

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