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I am Lyosha [343]
2 years ago
11

What is the volume of a sphere with a radius of 9.2 cm, rounded to the nearest tenth of a cubic centimeter?

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
8 0

Answer:

3262.9 cm^3

Step-by-step explanation:

Formula =

\frac{4}{3}  \times \pi r ^{3}

Pi = 3.145

So,

\frac{4}{3}  \times 3.145 \times 9.2 ^{3}  \\   =  3262.183595 \\  = 3262.9 cm^{3}

Here you go

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chubhunter [2.5K]

Answer:

13 square units

Step-by-step explanation:

You <em>could</em> calculate the length of each side using Pythagorean theorem, then use Heron's formula to find the area.  But there's an easier way: find the area of the rectangle that contains the triangle, and subtract the areas of the smaller triangles in the corners.

The area of the rectangle is 4 × 7 = 28.

The area of the upper left triangle is ½(2)(4) = 4.

The area of the upper right triangle is ½(3)(5) = 7.5.

The area of the lower right triangle is ½(1)(7) = 3.5.

So the area of the triangle is:

28 − 4 − 7.5 − 3.5 = 13

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3 years ago
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AURORKA [14]
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Answer:

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