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3 years ago

How do you write 14.8 as a mixed fraction Step by step method please?

1 answer:

lisabon 2012 [21]3 years ago

5 0

$14.8=14+0.8\\\\0.8=\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\\\\therefore\\\\14.8=14+\dfrac{4}{5}=\boxed{14\frac{4}{5}}$

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A temperature record in Antarctica was -120.the temperature recorded in the Sahara desert was 129.how many degrees warmer is 129

allochka39001 [22]

129 is 249 degrees warmer than -120 because -120+120=0 and then you add 129 to 0 which is 129. that means you add 120 and 129 to get 249

7 0

3 years ago

What in slope-intercept form, can go through the line ( a, 2a) and (-5a, 6a)

Wittaler [7]

Answer:

y = -2/3x + 8/3a

Step-by-step explanation:

Given points

(a, 2a) and (-5a, 6a)

Slope-intercept form

y = mx + b

Slope of the line is

m = (6a - 2a)/( -5a - a) = 4a/(-6a) = - 2/3

The y-intercept is:

2a = -2/3*a + b
b = 2a + 2/3a
b= 8/3a

So the line is:

y = -2/3x + 8/3a

7 0

3 years ago

Read 2 more answers

What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%2A%2081" id="TexFormula1" title="\frac{2}{3} * 81" alt="\frac

Vaselesa [24]

Hello!

Answer: ⇒⇒⇒⇒⇒⇒⇒ =54

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Step-by-step explanation:

First you had to convert element to fraction.

$\frac{2}{3}*\frac{81}{1}$

Then you had to cross out by the common factor of 3.

$\frac{2}{1}=\frac{27}{1}$

Multiply by the fraction.

$\frac{2*27}{1*1}$

Multiply by the number.

$2*27=54$

$=\frac{54}{1*1}$

Again multiply by the number.

$1*1=1$

$=\frac{54}{1}$

Apply rule.

$\frac{54}{1}=54$

54 is the right answer.

______________________________________________________________

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

_________________________________________________________________

4 0

3 years ago

The histogram shows the number of miles walked one weekend by people in a hiking club.

dusya [7]

The answer is D because all the rest of the statments are untrue. d is also right because 4 people walked 3-5 miles and 3 people walked 6-8 miles and as you know, 3+4=7

3 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago