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Klio2033 [76]
3 years ago
11

WHO CAN ANSWER I WILL BRAINLY AND POINTS

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer:

need poins

Step-by-step explanation:

d

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2 years ago
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Graph a system of equations to solve log (−5.6x + 1.3) = −1 − x. Round to the nearest tenth.
const2013 [10]

From the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2

the answers are -2.1 and 0.2.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two systems of the equation:

y = log (−5.6x + 1.3)

y  = −1 − x

After plotting the above equation on the graph we will see two intersections point:

(-2.12, 1.12) and (0.221, -1.221)

So the least value is x = -2.12 ≈ -2.1

The greatest value is x = 0.221 ≈ 0.2

Thus, from the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2

the answers are -2.1 and 0.2.

Learn more about the linear equation here:

brainly.com/question/11897796

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8 0
2 years ago
Find a.<br> Round to the nearest tenth:<br> 2 cm<br> с<br> 150<br> 1050<br> a =<br> = [? ]cm
VLD [36.1K]

Answer:

a = 1.8 cm

Step-by-step explanation:

Here. we want to find the value of a

To do this, we are going to use the sine rule

it states that the ratio of a side and the sine of the angle that faces the side is a constant for all the sides of a triangle

From the diagram, we have that;

The angle facing a is;

180-15-105 = 60

So, we have that

a/sin 60 = 2/sin 105

a = 2sin 60/sin 105

a = 1.794 cm

6 0
3 years ago
Please help me with 14 a,b,c thank you
tresset_1 [31]
It is in the attachment.
Let me know if this helps.
also let me know if it shows up for you and if it don't ill post your answer in the comments.

8 0
3 years ago
Simplify the monomials
Zielflug [23.3K]

Answer:

(4a)^{-3}*^{-4}

x^m*x^n=x^{m+n}

(4a)^{-3}*a^{-4}

(-4)^{-3}\: a^{-3}*a^{-4}

4^{-3}\:a^{-3-4}

\cfrac{1}{4^3} \:a^{-7}

\boxed{\frac{1}{64a^{7}} }

~

(3xy)^2*(-4x^3y^2)^3

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64\:a^{-3}b^{15}c^{-9}

\boxed{\frac{64b^{15}}{a^3c^9}}

7 0
2 years ago
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