First you plug in for x,
2(y-3)+y=12
Then you solve for y
2y-5+y=12
-10y+y=12
-9y=12
-9y/9=12/-9
y=-1.333333333333333333333333333333333333333333333333333333333
Answer:
the answer is B the image will be in quadrant III
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
The height formula given is:
h = -16t^2 + 70
That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.
If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:
6 = -16t^2 + 70
16t^2 = 64
t^2 =4
t = 2 s
So, it will take 2 seconds for the object to be 6 feet above the valley floor.
"r < 3 or r > 2" is the one among the following choices given in the question that <span>could have resulted in this solution set. The correct option among all the options that are given in the question is the fourth option or option "d". I hope that this is the answer that has actually come to your desired help.</span>
X(x+1) 1(x+4)
x^2+x+x+4
x^2+2x+4
