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Tanzania [10]
2 years ago
13

When a constant force acts

Mathematics
1 answer:
yan [13]2 years ago
7 0

Answer:

25

Step-by-step explanation:

First expression: A= k/M

when A = 15 and M = 5, k = A×M = 75

therefore, when M = 4, A = 75/3 = 25

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John has 300 watermelons. He sells 150. How many does he have?
oksian1 [2.3K]

Answer:

150

Step-by-step explanation:

300-150

6 0
3 years ago
a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.​
Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = <u>6.15</u><u> </u><u>N</u>

<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>effort</u><u> </u><u>applied</u><u> </u><u>=</u><u> </u><u>6.15</u><u> </u><u>N</u>

<u>Hope</u><u> </u><u>this</u><u> </u><u>answer</u><u> </u><u>helped</u><u> </u><u>you</u><u>.</u><u>.</u>

<u>Please</u><u> </u><u>mark</u><u> </u><u>me</u><u> </u><u>as</u><u> </u><u>brainliest</u><u> </u>

8 0
11 months ago
Find the height of a rectangle with a base of 11 in and area of 120 in2
Mrac [35]

Answer:

that is the solution to the question

3 0
3 years ago
1 Solve the compound inequality 4x&gt;-16 or 6x &lt;-48<br>​
Yuliya22 [10]

Answer:

Step-by-step explanation:

4x > -16 reduces to x > -4:  All numbers greater than x = -4 (shaded area to the right of -4).

6x < -48 reduces to x < -8:  All numbers to the left of -8 (shaded area to the left of -8).

Solution:  (-infinity, -4) ∪ (-8, infinity)

The number line between -8 and -4 is not part of the solution set (is not shaded or darkened)

Draw an open circle at -8 and extend an arrow to the left of this circle.  Then draw an open circle at -4 and extend an arrow to the right of this circle.

5 0
2 years ago
The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.
Vika [28.1K]

Given that average mass of an ant = 3 \times 10^{-3}grams.

Given that average mass of a giraffe = 2 \times 10^{3} Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g


So the average mass of a giraffe = 2 \times 10^{3} *10^3 grams.


Now we just need to divide mass of giraffe by mass of ant to find the answer.

\frac{2 \times 10^{3} *10^3 }{3 \times 10^{-3} }

= \frac{2 \times 10^{3} *10^3 *10^{3}}{3  }

= \frac{2 \times 10^{3+3+3}}{3  }

= \frac{2 \times 10^9}{3  }

= \frac{2}{3  } \times 10^9

=666666666.667

Hence final answer is \frac{2}{3  } \times 10^9 which is approx 666666666.667.

3 0
3 years ago
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