Answer:
![\sf 13m+16p](https://tex.z-dn.net/?f=%5Csf%2013m%2B16p)
Step-by-step explanation:
![\sf 9m+p+12p+4m+3p](https://tex.z-dn.net/?f=%5Csf%209m%2Bp%2B12p%2B4m%2B3p)
![\sf combine \:like \:terms](https://tex.z-dn.net/?f=%5Csf%20combine%20%5C%3Alike%20%5C%3Aterms)
![\sf \:9m+4m=13m](https://tex.z-dn.net/?f=%5Csf%20%5C%3A9m%2B4m%3D13m)
![\sf p+12p+3p=16p](https://tex.z-dn.net/?f=%5Csf%20p%2B12p%2B3p%3D16p)
![\sf 13m+16p](https://tex.z-dn.net/?f=%5Csf%2013m%2B16p)
G(x) = 3x² - 5x + 7
b) g(-2) ==> Substitude -2 into x
g(-2) = 3(-2)² - 5(-2) + 7
g(-2) = 12 + 10 + 7
g(-2) = 29
c) g(4) ==> Substitude 4 into x
g(4) = 3(4)² - 5(4) + 7
g(4) = 48 - 20 + 7
g(4) = 35
d) g(-x) ==> Substitude -x into x
g(-x) = 3(-x)² - 5(-x) + 7
g(-x) = -3x² + 5x + 7
e) g(1 - t) ==> Substitude 1 - t into x
g(1 - t) = 3(1 - t)² - 5(1 - t) + 7
g(1 - t) = 3(1 - 2t + t²) - 5 + 5t + 7
g(1 - t) = 3 - 6t + 3t² - 5 + 5t + 7
g(1 - t) = 3t² - t + 5
Answer:
The answer to your question is 8.5 m
Step-by-step explanation:
Data
angle = Ф = 12°
dept = 40 m
distance from the ship to the treasure = ?
Process
To solve this problem use trigonometric functions. The trigonometric function that relates the Opposite side and the adjacent side is tangent.
tan Ф = Opposite side / Adjacent side
-Solve for Opposite side
Opposite side = Adjacent side x tanФ
-Substitution
Opposite side = 40 x tan 12
-Simplification
Opposite side = 8.5 m
Option A he would be paid:
$15 per session
Option B he would be paid:
$20 per session
Equations
A: Y = 15x + 17250
B: Y = 20x + 14000
When X = 650 the Y values of A and B are equal.
<em>After 650 training sessions, they would be equal.</em>
Answer:
x = 12
Step-by-step explanation:
(8x - 34) and (5x + 2) are alternate angles and congruent, then
8x - 34 = 5x + 2 ( subtract 5x from both sides )
3x - 34 = 2 ( add 34 to both sides )
3x = 36 ( divide both sides by 3 )
x = 12