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Bingel [31]
2 years ago
5

How many three-letter "words" can Bob make using just these letters?

Mathematics
1 answer:
alekssr [168]2 years ago
4 0

Answer:

two

Step-by-step explanation:

the two "words" Bob can make using the three letters t, o, and a are;

oat and tao

hope this helps

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What are the possible polynomial expression for dimensions of the cuboid whose volume is 12y2 + 8y -20
bogdanovich [222]

Answer:

The answer is below

Step-by-step explanation:

The volume of a cuboid is the product of its length, height and breadth. It is given by:

Volume = length × breadth × height

Since the volume is given by the expression 12y² + 8y - 20. That is:

Volume = 12y² + 8y - 20 = 4(3y² + 2y - 5) = 4(3y² + 5y - 3y -5) = 4[y(3y + 5) -1(3y + 5)]

Volume = 4(y-1)(3y+5)

Or

Volume = 12y² + 8y - 20 = 2(6y² +4y - 10) = 2(6y² + 10y - 6y -10) = 2[y(6y + 10) -1(6y + 10)]

Volume = 2(y-1)(6y+10)

Therefore the dimensions of the cuboid are either 4, y-1 and 3y+5 or 2, y-1 and 6y+10

3 0
3 years ago
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Is the product of two imaginary numbers always imaginary?
Diano4ka-milaya [45]
No. i*i = -1

2i*3i=-6

now if they meant complex numbers the answer is still no

(2+4i)(2-4i) = 4-8i+8i-16 = -12
3 0
3 years ago
2 geometry questions.. will mark brainliest
Andru [333]
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What congruent theorem is this triangle...need help please
agasfer [191]
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3 years ago
What is the area of the shaded region below?<br> 7 m<br> 30 m<br> 7 m<br> 21 m
Rama09 [41]

Answer:

322.28

A

Step-by-step explanation:

Area of the rectangle

L = 30

W = 21

Area = 30 * 21

Area = 630

Area of the circles

Radius = 7 m

Area = pi r^2

Area = 3.14 * 7^2

Area = 153.86 m^2

Area of both circles = 307.72

Area of the Shaded Region

Area of shaded region = area of the rectangle - area of 2 circles.

Area of Shaded Region = 630 - 307.72

Area of Shaded Region = 322.28

5 0
3 years ago
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