What is the simplified form of -9m^-2n^5 times 2m^-3n^-6

A plant is 3 inches tall when you purchase it and grows 2 inches per month. Write an equation in slope intercept form that repre

tresset_1 [31]

Answer:

y = 3 + 2x

Step-by-step explanation:

In this scenario, we are given two values which are the initial height of the plant and its growth height. Then we are given a variable which is the number of months (x) that are unknown for us. The growth height needs to be multiplied by the number of months to know how much it has grown in that time period. Then we add this value to the initial height of the plant to calculate the total height (y) of the plant after x number of months. We can apply this information to form the following equation in slope-intercept form.

y = 3 + 2x

5 0

3 years ago

What is the volume? 7 cm 5 cm 8 cm cubic centimeters

Flura [38]

Answer:

280 cm

or 280cm^2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

(-1, 4) and (1,-1) And (0,-8) and 3,2)

Free_Kalibri [48]

Answer:

These are all points on a graph. I'm not sure what you're asking.

7 0

3 years ago

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis

Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

$f(x)=6$

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

$f(x)=-3$

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

$f(x)=1$

Therefore the graph represents a piecewise function, which is defined as

$f(x)=\begin{cases}6& \text{ if } x2 \end{cases}$

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

$lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)$

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

$lim_{x\rightarrow 2^-}f(x)=6$

$lim_{x\rightarrow 2^+}f(x)=-3$

$6\neq-3$

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0

3 years ago

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Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

Equation Solving

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$