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Fed [463]
2 years ago
6

Jacob sells his motorbike for £112 making a loss of 12% on its original price. Work out its original price

Mathematics
1 answer:
liq [111]2 years ago
4 0

Answer:

125,44

Step-by-step explanation:

Loss = 112÷100*12

=13,44

Therefore : 112 + 13%

=112 + 13,44

=125,44

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Find the minimum value of C=2x+y subject to the following constraints: <br> Please help me!!
-BARSIC- [3]

Answer:

The minimum value of C is 20

Step-by-step explanation:

we have

2x+3y\geq 24 ----> constraint A

4x+y\geq 38 ----> constraint B

x\geq 0 ----> constraint C

y\geq 0 ----> constraint D

Using a graphing tool

The solution set of the constraints is the shaded area

see the attached figure

The vertices of the shaded area are (0,38),(9,2) and (12,0)

To determine the minimum value of C substitute the values of x and y of each vertex in the objective function and then compare the results

C=2x+y

For (0,38) ---> C=2(0)+38=38

For (9,2) ---> C=2(9)+2=20

For (12,0) ---> C=2(12)+0=24

therefore

The minimum value of C is 20

7 0
3 years ago
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anastassius [24]

I'm sorry I can't see it, it is blocked.

7 0
2 years ago
Read 2 more answers
For which values of P and Q does the following equation have infinitely many solutions ?
Rzqust [24]
I’d say the answer would be d
7 0
3 years ago
Please answer correctly !!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!
Ugo [173]

Answer:

Step 3  they took the square root incorrectly

Step-by-step explanation:

5 ( x-2)^2 +6 = 86

Subtract 6 from each side

5 ( x-2)^2 +6 -6= 86-6

5 ( x-2)^2  = 80

Divide each side by 5

5 ( x-2)^2  /5 = 80/5

(x-2)^2 = 16

Take the square root of each side

sqrt((x-2)^2)  = ±sqrt(16)

x-2 = ±4

4 0
2 years ago
the earth rotates about its axis once every 23 hours, 56 minutes and 4 seconds. Approximate the number of radians the earth rota
marishachu [46]

Answer:

\frac{\pi}{43082}\text{ radians per second}

Step-by-step explanation:

Given,

Time taken in one rotation of earth = 23 hours, 56 minutes and 4 seconds.

Since, 1 minute = 60 seconds and 1 hour = 3600 seconds,

⇒ Time taken in one rotation of earth = (23 × 3600 + 56 × 60 + 4) seconds

= 86164  seconds,

Now,  the number of radians in one rotation = 2π,

That is, 86164 seconds = 2π radians

\implies 1\text{ second }=\frac{2\pi}{86164}=\frac{\pi}{43082}\text{ radians}

Hence, the number of radians in one second is \frac{\pi}{43082}

4 0
3 years ago
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