2 years ago

Jacob sells his motorbike for £112 making a loss of 12% on its original price. Work out its original price

Mathematics

1 answer:

liq [111]2 years ago

4 0

Answer:

125,44

Step-by-step explanation:

Loss = 112÷100*12

=13,44

Therefore : 112 + 13%

=112 + 13,44

=125,44

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Given:

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The value of $(h\circ g)(-6)$ .

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We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

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Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

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Therefore, the value of $(h\circ g)(-6)$ is 2401.

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