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Andrew [12]
2 years ago
9

HELP PLEASE. Check picture. I have tried but cannot seem to get it.

Mathematics
2 answers:
alexandr1967 [171]2 years ago
5 0

Answer:

884^{-7

Step-by-step explanation:

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

Before we begin solving, let's review a few rules of exponents.

  1. If an <u>exponent</u> is multiplying with another <u>exponent</u> and their bases are the same, you can simply add the <u>exponents.</u>
  2. If an <u>exponent</u> is dividing with another <u>exponent</u> and their <u>bases</u> are the same, you can simply subtract the <u>exponents.</u>

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

  • ⇒ \dfrac{884^{97} }{884^{58} \times 884^{46}  }

  • ⇒ \dfrac{884^{97} }{884^{58 + 46}}                                                                                       [#1]

  • ⇒ \dfrac{884^{97} }{884^{104}}

  • ⇒ 884^{97 - 104                                                                                     [#2]

  • ⇒ \boxed{884^{-7}}

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

Sauron [17]2 years ago
4 0

Answer:

884^{-7}

Step-by-step explanation:

Start by simplifying the denominator of the fraction. When multiplying exponents of the same base, you can add the exponents. This is also known as the product rule.

a^x\cdot a^y=a^{x+y}

["a" is the base, and "x" and "y" are the exponents]

Using this we find...

884^{58}\cdot884^{46}=884^{58+46}=884^{104}

When dividing exponents of the same base, you can subtract the exponents. This is also knows as the quotient rule.

a^x\div a^y=a^{x-y}

Using this we find...

\frac{884^{97}}{884^{104}}=884^{97-104}=884^{-7}

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