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melisa1 [442]
2 years ago
15

Derive an expression for the block's centripetal acceleration ac in terms of m , θ , and physical constants, as appropriate

Physics
1 answer:
maxonik [38]2 years ago
7 0

The expression for the block's centripetal acceleration is derived as ω²r or v²/r.

<h3>What is centripetal acceleration?</h3>

The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.

The expression for the block's centripetal acceleration is derived as follows;

ω = dθ/dt

where;

  • ω is the angular speed
  • θ is the angular displacement
  • t is the time of motion

ac = ω²r

where;

  • r is the radius of the circular path

Also, ω = v/r

ac = (v/r)²r

ac = v²/r

Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.

Learn more about centripetal acceleration here: brainly.com/question/79801

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