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Dominik [7]
3 years ago
12

If a wave has amplitude of 0.2 meters, a wavelength of 0.5 meters, and a frequency of 32 Hz, at what speed is it moving?

Physics
1 answer:
GarryVolchara [31]3 years ago
3 0
The velocity, frequency and wavelength of a wave are related by:
v = fλ
v = 32 x 0.5
v = 16 m/s
The answer is B.
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Which component of weight is cause for S.H.M of bob simple pendulum
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Explanation:

The Simple Pendulum. A simple pendulum is defined to have a point mass, also known as the pendulum bob, which is suspended from a string of length L with negligible mass ((Figure)). Here, the only forces acting on the bob are the force of gravity (i.e., the weight of the bob) and tension from the string.

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6 0
2 years ago
What is the acceleration of a car that goes from 0 to 20m/s in 7 seconds?
nadezda [96]

Answer:

2m/s^2

Explanation:

Clculate the acceleration:

V = u +at

20m/s = 0 + a*10s

a = 20m//10s

a = 2m/s²

From the data given , it is not possible to calculate the displacement , because no direction of motion is given

But it is possible to calculate the distance travelled

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6 0
2 years ago
A 20 μF capacitor initially charged to 30 μC is discharged through a 1.5 kΩ resistor. Part A How long does it take to reduce the
Natasha_Volkova [10]

Answer:

it will take 36.12 ms to reduce the capacitor's charge to 10 μC

Explanation:

Qi= C×V

then:

Vi = Q/C = 30μ/20μ = 1.5 volts

and:

Vf = Q/C = 10μ/20μ = 0.5 volts

then:

v = v₀e^(–t/τ)  

v₀ is the initial voltage on the cap  

v is the voltage after time t  

R is resistance in ohms,  

C is capacitance in farads  

t is time in seconds  

RC = τ = time constant  

τ = 20µ x 1.5k = 30 ms  

v = v₀e^(t/τ)  

0.5 = 1.5e^(t/30ms)  

e^(t/30ms) = 10/3  

t/30ms = 1.20397

t = (30ms)(1.20397) = 36.12 ms

Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.

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3 years ago
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Irina-Kira [14]
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3 years ago
Read 2 more answers
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Aleksandr-060686 [28]

Answer:

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Hope this helps!!!!

Explanation:

8 0
2 years ago
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