To answer the question above, we need to c<span>onvert 12.8 g to moles by dividing by 46.07 first.</span>
<span>For every mole you burn, you get 1235 kJ of heat. So multiply your number of moles by 1235. It'll be something in the neighborhood of 500. </span>
<span>Take your kJ that you calculated and divide by 5.65 to get the number of degrees that your calorimeter goes up. Add that to 25.
I hope my answer helped you</span>
I believe its G because it has the same amount of particles. (I haven't had much background)
Answer:
The radius of an atom can only be found by measuring the distance between the nuclei of two touching atoms, and then halving that distance. The type of atomic radius being measured here is called the metallic radius or the covalent radius depending on the bonding.
Explanation:
(Pls mark me brainliest if you can)
<span>One degree Celsius indicates the same temperature change as one </span>
Answer:
Explanation:
Given that:
The flow rate Q = 0.3 m³/s
Volume (V) = 200 m³
Initial concentration 
= 2.00 ms/l
reaction rate K = 5.09 hr⁻¹
Recall that:
where;
Thus; the concentration of species in the reactant = 102.98 mg/l
b). If the plug flow reactor has the same efficiency as CSTR, Then:
![t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]](https://tex.z-dn.net/?f=t%20_%7BPFR%7D%20%3D%20%5Cdfrac%7B1%7D%7Bk%7D%20%5CBig%20%5B%20In%20%28%20%5Cdfrac%7BC_o%7D%7BC_e%7D%29%20%5CBig%20%5D)
![\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]](https://tex.z-dn.net/?f=%5Cdfrac%7BV_%7BPFR%7D%7D%7BQ_%7BPFR%7D%7D%20%3D%20%5Cdfrac%7B1%7D%7Bk%7D%20%5CBig%20%5B%20In%20%28%20%5Cdfrac%7BC_o%7D%7BC_e%7D%29%20%5CBig%20%5D)
![\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]](https://tex.z-dn.net/?f=%5Cdfrac%7BV_%7BPFR%7D%7D%7BQ_%7BPFR%7D%7D%20%3D%20%5Cdfrac%7B1%7D%7B5.09%7D%20%5CBig%20%5B%20In%20%28%20%5Cdfrac%7B200%7D%7B102.96%7D%29%20%5CBig%20%5D)
![\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]](https://tex.z-dn.net/?f=%5Cdfrac%7BV_%7BPFR%7D%7D%7BQ_%7BPFR%7D%7D%20%3D0.196%20%5CBig%20%5B%20In%20%28%201.942%29%20%5CBig%20%5D)
The volume of the PFR is ≅ 140 m³
