If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
For the first one it’s 9490 & for the second it’s 860
(22 x sin(65))/sin(53) =24.96604654 rounded of to nearest tenth = 25
So X = 25
