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Marrrta [24]
2 years ago
10

A long solenoid with radius r = 7 cm and n = 3,170 turns/m carries a current i = 6. 7 a. What is the magnitude of the magnetic f

ield in the central area inside the solenoid, in t?
Mathematics
1 answer:
kondaur [170]2 years ago
6 0

The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

<h3>Magnetic field inside solenoid</h3>

The magnetic field inside the central area of the solenoid is given by B = μ₀ni where

  • μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A,
  • n = number of turns per unit length = 3,170 turns/m and
  • i = current in solenoid = 6.7 A

Since B = μ₀ni

Substituting the values of the variables into the equation, we have

B = μ₀ni

B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A

B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m

B = 84956π × 10⁻⁷ T

B = 266897.15 × 10⁻⁷ T

B = 0.026689715 T

B ≅ 0.0267 T

So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

Learn more about magnetic field inside a solenoid here:

brainly.com/question/25562052

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Answer:

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Step-by-step explanation:

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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