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valina [46]
2 years ago
13

Please help me, I don't know the answer WILL MARK BRANLIEST IF CORRECT :)

Mathematics
2 answers:
LuckyWell [14K]2 years ago
7 0

Answer:

the answer is C

Step-by-step explanation:

emmasim [6.3K]2 years ago
5 0

Answer:

the answer is C ........

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When traveling to Europe, Bailey converts the temp. given in degrees Celsius to a Fahrenheit temp. by using the expression 9x ÷
lawyer [7]

9(15) / 5 + 32

135 / 5 + 32

27 + 32

59

5 0
3 years ago
Read 2 more answers
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Which type of statement has the form "if A, then B"?
fiasKO [112]
I think it would be conditional, because B depends on A. Of A is false, then B isn’t possible, making it conditional.
4 0
3 years ago
Read 2 more answers
1 and 2 are complementary angles. 1 and 3 are vertical angles. If
Marizza181 [45]

If angle 1 and angle 2 are <u>complementary, </u>then they add up to 90 degrees. We are given that angle 2 equals 52 degrees.

So we subtract and get our answer:

38

That's NOT the final answer.

The next step is:

Angle 1 and angle 3 are vertical angles.

Vertical angles are congruent.

So if angle 1 is 38, then angle 3 is also 38.

Now, supplementary angles add up to 180 degrees.

So that's the answer:

180-38=142

142 is the supplement of angle 3.

Hope it helps! :)

Answered by

***ROSALIND***

8 0
3 years ago
(-5)^2-2x(-9)+6<br> Please show work and step by step.
Varvara68 [4.7K]

Answer:

<h2>49</h2>

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

==============================================

(-5)² - 2 × (-9) + 6          <em>first </em><em>E</em><em>xponents</em>

25 - 2 × (-9) + 6          <em>next </em><em>M</em><em>ultiplication</em>

25 + 18 + 6              <em>next </em><em>A</em><em>ddition</em>

43 + 6 = 49

5 0
3 years ago
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