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kupik [55]
2 years ago
8

A nitrogen bubble with a volume of 0.0050 mL forms in the joint of a scuba diver as she ascends rapidly from a pressure of 4.1 a

tm to the surface, with a pressure of 1.0 atm. What is the volume of the bubble at the surface
Chemistry
1 answer:
Lina20 [59]2 years ago
3 0

As the scuba diver ascends rapidly to the surface at the given pressure, the volume of the nitrogen bubble at the surface becomes 0.021mL.

Given the data in the question;

  • Initial volume; V_1 = 0.005mL
  • Initial pressure; P_1 = 4.1atm
  • Final pressure; P_2 = 1.0atm\\

Final volume; V_2 = \ ?

<h3>Boyle's law</h3>

Boyle's law states that the volume V of a given quantity of gas is inversely proportional to its pressure P as long as temperature remains constant.

Boyle's law is expressed as;

P_1V_1 = P_2V_2

Where P_1 is Initial Pressure, V_1 Initial volume, P_1 is Final Pressure and P_2 is Final volume.

P_1V_1 = P_2V_2\\\\V_2 = \frac{P_1V_1}{P_2} \\\\V_2 = \frac{4.1atm \ *\ 5.0*10^{-6}L}{1.0atm}\\ \\V_2 = \frac{4.1 \ *\ 5.0*10^{-6}L}{1.0}\\\\V_2 = 2.05*10^{-6}L\\\\V_2 = 0.021mL

Therefore, as the scuba diver ascends rapidly to the surface at the given pressure, the volume of the nitrogen bubble at the surface becomes 0.021mL.

Learn more about Boyle's law: brainly.com/question/1437490

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Which pair of elements would most likely combine to form a salt? I and F Cs and I Na and C N and F
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If n=7 and l=6, What are the values of l?​
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Can somebody please help me with this question, I'm very confused! I thought i did it right because i found Kb and the conc. of
andrew-mc [135]
Let's investigate the substances involved in the reaction first. The compound <span>CH3NH3+Cl- is a salt from the weak base CH3NH2 and the strong acid HCl. When this salt is hydrated with water, it will dissociate into CH3NH2Cl and H3O+:

CH3NH3+Cl- + H2O </span>⇒ CH3NH2Cl + H3O+

Nest, let's apply the ICE(Initial-Change-Equilibrium) table where x is denoted as the number of moles used up in the reaction:

                 CH3NH3+Cl- + H2O ⇒ CH3NH2Cl + H3O+
Initial                  0.51                             0               0
Change                 -x                             +x             +x
-------------------------------------------------------------------------------
Equilibrium        0.51 - x                         x               x

Then, let's find the equilibrium constant of the reaction. Since the reaction is hydrolysis we use KH, which is the ratio of Kw to Ka or Kb. Kw is the equilibrium constant for water hydrolysis which is equal to 1×10⁻¹⁴. Since the salt comes from the weak base, we use Kb. Since pKb = 3.44, then. 3.44 = -log(Kb). Thus, Kb = 3.6307×10⁻⁴ 

KH = Kw/Kb = (x)(x)/(0.51 - x)
1×10⁻¹⁴/ 3.6307×10⁻⁴ = x²/(0.51-x)
x = 3.748×10⁻⁶

Since x from the ICE table is equal to the equilibrium concentration of H+, we can find the pH of the aqueous solution:

pH = -log(H+) = -log(x)
pH = -log ( 3.748×10⁻⁶)
pH = 5.43
6 0
3 years ago
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