Question

A nitrogen bubble with a volume of 0.0050 mL forms in the joint of a scuba diver as she ascends rapidly from a pressure of 4.1 atm to the surface, with a pressure of 1.0 atm. What is the volume of the bubble at the surface

Answer 1

As the scuba diver ascends rapidly to the surface at the given pressure, the volume of the nitrogen bubble at the surface becomes 0.021mL.

Given the data in the question;

• Initial volume; $V_1 = 0.005mL$

• Initial pressure; $P_1 = 4.1atm$

• Final pressure; $P_2 = 1.0atm$

Final volume; $V_2 = \ ?$

Boyle's law

Boyle's law states that the volume V of a given quantity of gas is inversely proportional to its pressure P as long as temperature remains constant.

Boyle's law is expressed as;

$P_1V_1 = P_2V_2$

Where $P_1$ is Initial Pressure, $V_1$ Initial volume, $P_1$ is Final Pressure and $P_2$ is Final volume.

$P_1V_1 = P_2V_2\\\\V_2 = \frac{P_1V_1}{P_2} \\\\V_2 = \frac{4.1atm \ *\ 5.0*10^{-6}L}{1.0atm}\\ \\V_2 = \frac{4.1 \ *\ 5.0*10^{-6}L}{1.0}\\\\V_2 = 2.05*10^{-6}L\\\\V_2 = 0.021mL$

Therefore, as the scuba diver ascends rapidly to the surface at the given pressure, the volume of the nitrogen bubble at the surface becomes 0.021mL.

Learn more about Boyle's law: brainly.com/question/1437490